Question

Can someone write (1,-8); m=5 in standard form and point slope form?

Answer 1

first..use the point slope form
\[y - y_1 = m(x-x_1)\]

in this case your is 5 and x1 is 1 and y1 is -8

so the equation becomes
\[y -(-8) = 5(x-1)\]
following so far?

Answer 2

Yes I am

Answer 3

so that is the point-slope form..to get the standard from, just simplify
\[\implies y + 8 = 5x - 5\]
put everything on one side
\[\implies 5x - y - 5 - 8 = 0\]
combine like terms...
\[\implies 5x - y - 13 = 0\]
^standard form

got it?