determine the limit of the trig function:

lim as x approaches 0
sinx(1-cosx) / 2x^2

help plz

Question

determine the limit of the trig function:

lim as x approaches 0
sinx(1-cosx) / 2x^2


help plz

anonymous · Answer

use a calculator

australopithecus · Answer

you cannot divide by zero cycle

anonymous · Answer

Really??? @cyclevleoce12345

anonymous · Answer

i have to solve it analytically. no calculators allowed in AP

anonymous · Answer

if u were in ap, you should not need this website, I'm here to help people not give them answers

anonymous · Answer

We know:
$$
\lim_{x\to 0}\frac{1-\cos(x)}{x}=0\
\lim_{x\to 0}\frac{\sin(x)}{x}=1
$$So, we use such, and find that:
$$
\lim_{x\to 0}\frac{\sin(x)}{x}\frac{1-\cos(x)}{x}\frac{1}{2}=0
$$Since the limit of the product equals the product of the limits.

anonymous · Answer

keep trying

anonymous · Answer

@satellite73 Who was that to?

anonymous · Answer

@LolWolf  person was trying unsuccessfully to use profanity. it was amusing