Question

Can someone please explain how the value of x in the equation below came to be 4.464348

Answer 1

\[e^(4x)=96e^(3x)\]

Answer 2

the answer is actually 4.5643

first we take the natural log of both sides,

\[\ln (e ^{4x}) = \ln (96e ^{3x})\]

the left side simplifies, and we use the property of logs to get

\[4x = \ln 96 + \ln (e ^{3x}) = \ln96 + 3x\]

Answer 3

Thanks so much Shi

Answer 4

np :)