A circular swimming pool has a diameter of 24ft, the sides are 5 ft high, and the depth of the water is 4 ft. How much work is required to pump all of the water out over the side? (Use the fact that water weighs 62.5 lb/ft^3)

Question

lgbasallote · Answer

a circle has sides?

anonymous · Answer

It's a pool, and the sides of the pool are 5ft high.

anonymous · Answer

Do you happen to have the equation for work?

anonymous · Answer

I have absolutely no idea, I got completely stuck on this one.  I know that the equation for work is W=FdeltaX

anonymous · Answer

I think with W = F dx,  F = weight of water  dx = height moved

so F = density*Volume*gravity coefficient
and you integrate from 0 to 4

anonymous · Answer

ah thats not really reliable, but this person seems to have solved your problem http://answers.yahoo.com/question/index?qid=20090410195413AAnHzUh

anonymous · Answer

hahaha thanks for that I'll follow the steps from that.  I appreciate it!