Question

Factor completely: a^3-2a^2-4a+8

Answer 1

\[(a^3 - 2a^2) - (4a + 8)\]

Can you factor out a^2 from first bracket and 4 from second brackets??

Answer 2

Something went wrong..

Answer 3

\[(a^3 - 2a^2) - (4a - 8)\]

Answer 4

there are no brackets on my paper.

Answer 5

I have just grouped them..

Answer 6

You can write as you want without brackets..

Answer 7

oh okay. sorry i got confused.

Answer 8

i don't know how to factor it.

Answer 9

see the 1st example to know how u can factor,the cubic equation,just remove=0,there:
http://openstudy.com/study#/updates/504335bee4b000724d4620b4

Answer 10

Wait..

\[a^3 - 2a^2 - 4a + 8\]

Answer 11

what can u take out common from first two terms?