7/2x-1=2x+5. solve the equation?

Question

anonymous · Answer

have this instead... http://www.wolframalpha.com/input/?i=7%2F2x-1%3D2x%2B5

anonymous · Answer

note the Universe is R but {1/2} b/c that makes the denominator zero.

now multiply both sides of the equation by 2x-1
you get 
7=(2x+5)(2x-1)
7=4x2+8x−5

now subtract 7 from both sides
you get 
4x ^{2} + 8x -12=0 (which is a quadratic equation)
now you can use the completing the square method or the quadratic formula to solve this 
you get
(x-1)(x+3)=0
so x=1 and x=-3 are the solutions

anonymous · Answer

if you want to know how I solved the quadratic equation here is how,

I have$$4x ^{2} + 8x -12=0$$
I divided both sides by 4
I get $$x ^{2} + 2x -3=0$$
now find two numbers when multiplied that give -3 and when added give 2
the numbers are 3 and -1
so the above quadratic equation can be written as $$x ^{2} + 3x -x -3$$
factoring gives
(x+3)(x-1)=0

anonymous · Answer

Done!

mayankdevnani · Answer

$$\frac{7}{2}x -1=2x+5$$
$$\frac{7x-2}{2} =2x+5$$
By Cross-Multiply_____
$$4x+10=7x-2$$
$$-3x=-12$$
$$x=4$$