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Mathematics 18 Online
OpenStudy (anonymous):

delete

OpenStudy (anonymous):

Would it be 50 pounds in the forward direction and the weight of the bow in the downward direction?

OpenStudy (anonymous):

@mathmate

OpenStudy (anonymous):

50 pounds in the forwards due to the tension, 50 pounds backwards due to you pulling it back to keep it stationary, so a net force of 0, as the forces cancel (opposite directions).

OpenStudy (anonymous):

If it had a net force of 0, then wouldn't it not shoot?

OpenStudy (anonymous):

Also\[force=mass*acceleration=mass*\frac{\text{change \in speed}}{\text{time taken for the change}}\]Acceleration is 0, so the net force is 0

OpenStudy (anonymous):

'when taking aim'- this is when it is not shooting. When it is shooting the force would not be 0, you are correct.

OpenStudy (anonymous):

Thanks!

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