Question

please what is the derivative of p(t)= 500/1+e^-t. thanks

Answer 1

i'm finding this one a bit tricky - not at my best today
i think you could do it using quotient rule:

dp(t)/ dt = (1+e^-t)*0 - 500( -e^-t)
----------------------
(1 + e^-t)^2

= 500e^-t
-------
(1 + e^-t)^2

Answer 2

well let me know what the derivative of e^-t is first?

Answer 3

using chain rule

its -1 * e^-t = -e^-t

Answer 4

yeah sure thanks

Answer 5

ok - tell you what i'll check it out on wolfram alpha - that doesn't make mistakes