The length of a cedar chest is twice its width. the cost/dm^2 of the lid is four times the cost/dm^2 of the rest of the cedar chest. if the volume of the cedar chest is 1440dm^3, find the dimensions so that the cost is minimum. begin by drawing a diagram sketch. whats a cedar chest. thanks

Question

anonymous · Answer

Refer to attached Mathematica solution.

khally92 · Answer

The question insisted that you begin by drawing a diagram, i guess its a cuboid? Want to thank you for your kind assistance and co-operation w=10.25 and h= 6.85.....

khally92 · Answer

Secondly i want to know if the dimensions of the width are height are in dm or cm. thanks once again.

anonymous · Answer

dm -> decimeter

The numbers were incorporated into the solution as presented in the problem statement.
The original metric dimensions could have been mm, cm

By the way, this is the first problem I have examined on this web site that used dm as the unit of length.

anonymous · Answer

"whats a cedar chest. thanks" http://www.wisegeek.com/what-is-a-cedar-chest.htm

khally92 · Answer

Thanks man. appreciate.