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Express cos x in terms of tan x/2
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I suppose you could use the tangent half-angle identity plus some other identity to do that..
From \[\tan(x/2)=\frac{\sin x}{1+\cos x} \rightarrow \cos x =\frac{\sin x}{\tan(x/2)} \space -1\]
Then you could use another identity to get sin x out of there.
Thank you so much for getting me started. I really appreciate the help.
Oh wait, you completly answered my question. Cos x is expressed in tan x/2. Again, I really appreciate the help.
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Hmm, maybe. I wouldn't be satisfied unless the only function on the right side was tan(x/2). It is pretty tricky to get that sin x out of there though, so if you're satisfied, I'm satisfied!
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