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How to solve this fractional equation x^2-2x+1/x-2=0?
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First, divide \(x - 2\) from \(x^2 - 2x + 1\), then solve that equation.
How?
can u divide by zero?
well u can't. so when you have \[ \large \frac{a}{b}=0 \] since b cannot be zero, the only possibility is a=0.
this means that your equation \[ \large \frac{x^2-2x+1}{x-2}=0 \] is just \[ \large x^2-2x+1=0 \]
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