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prove d/dx (square root of u) = 1/2*square root of u * du/dx
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Chain rule.
can u help pls..
\[{d \over dx} \sqrt{u} \implies {d \over dx} u^{1 \over 2} \implies {1 \over 2} \times \sqrt{u} \times {du \over dx}\]
That is chain rule!
yeah..
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help me pls..
hmm not sure this is a proof.
what class is this for?
differential calculus.. it is a chain rule
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