Question

okay so i cant get this equation 6(x+3) over 5=3x-3???????? im stupmed

Answer 1

\[\frac{6(x+3)}{5}=3x-3\]

start by multiplying both sides by 5 to get rid of the fraction

Answer 2

@mamacase Can you follow the above instruction?

Answer 3

im tryin to workit out

Answer 4

Show your work here, pls!

Answer 5

without te fractions it would b 6x+18=3x-3*5??

Answer 6

close but you need to multiply 5 to the entire right side
\[5*\frac{6(x+3)}{5}=(3x-3)*5\]
\[6(x+3)=5(3x-3)\]

Answer 7

although it looks like you understand how to distribute so im going to assume you know how to finish this problem

Answer 8

sooo 6x+18=15x-15??

Answer 9

yup

Answer 10

im gettin 33/9
not sure how

Answer 11

18+15= 33
15-6= 9

nothing is wrong with that answer

just simplify the fraction

Answer 12

ok so i gott anothr one 4(x-2) over 8=2(x+1) over 7? i kno 56 is te lcd!

Answer 13

you dont need LCD for this
you just need to cross multiply
or basically just multiply the LCD to both sides

Answer 14

ex. cross multiplication
\[\frac{1}{3}x=\frac{1}{2}x\]

\[2*x=3*x\]

Answer 15

i still dnt understand