okay so i cant get this equation 6(x+3) over 5=3x-3???????? im stupmed

Question

anonymous · Answer

$$\frac{6(x+3)}{5}=3x-3$$

start by multiplying both sides by 5 to get rid of the fraction

anonymous · Answer

@mamacase Can you follow the above instruction?

anonymous · Answer

im tryin to workit out

anonymous · Answer

Show your work here, pls!

anonymous · Answer

without te fractions it would b 6x+18=3x-3*5??

anonymous · Answer

close but you need to multiply 5 to the entire right side
$$5*\frac{6(x+3)}{5}=(3x-3)*5$$
$$6(x+3)=5(3x-3)$$

anonymous · Answer

although it looks like you understand how to distribute so im going to assume you know how to finish this problem

anonymous · Answer

sooo 6x+18=15x-15??

anonymous · Answer

yup

anonymous · Answer

im gettin 33/9
not sure how

anonymous · Answer

18+15= 33
15-6= 9

nothing is wrong with that answer

just simplify the fraction

anonymous · Answer

ok so i gott anothr one 4(x-2) over 8=2(x+1) over 7? i kno 56 is te lcd!

anonymous · Answer

you dont need LCD for this
you just need to cross multiply
or basically just multiply the LCD to both sides

anonymous · Answer

ex. cross multiplication
$$\frac{1}{3}x=\frac{1}{2}x$$

$$2*x=3*x$$

anonymous · Answer

i still dnt understand