Question

What are the zeros of the polynomial function: f(x) = x3 – x2 – 12x ?

Answer 1

i found the answer but thanks

Answer 2

First, we see that (x) exist in all the terms, so we can factor out an (x) and get:
f(x) = x^3 - x^2 - 12x

= x( x^2 - x -12)

Now we factor apart the (x^2 - x -12). What two numbers added together give -1 and multiplied together gives -12? I think it is -4 and 3, and I am pretty sure you go that too.
so:

x(x-4)(x+3), which means x = 0, 4,-3