Recall the vertical motion for when an object is dropped: h=-16t^2 + s where h = the height (feet), t = time in motion (seconds), and s = initial height (feet). If you drop a water balloon from a window 40 feet above the ground, then how long will it take for the water balloon to hit the ground? HELP ME!
s=40 solve for t when h=0
how exactly will the equation look when i solve for t?
0=-16t^2 +40 solve for t
subtract 40, divide by -16, find the square root
will it look kinda like this before i solve for the square root? 5/2=t^2
what the heck is the answer then? im, so terrible at math its unbelievable
t=sqrt{40/16} got a calculator?
no. its lost
oh i simplified thats where i got 5/2 but still.... no comprende
ok i got this but its wrong, i feel it. sqrt 10 over sqrt 2
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