Question

sketch the acceleration and position for this velocity graph

Answer 1

Okay, so my brother enjoys his physics, and he says this:

In your position time graph, it is going from maximum negative, but the slope is positive. It's positive because the general flow of the graph (from left to right) is going up.
Therefore, maximum positive velocity, and then it reaches the X axis, where it becomes 0. The apex is 0, it has 0 velocity. And the half of the position graph above the x axis is going at a maximum to a zero velocity, draw the tangents. The lines go from steeper to linear. And when it evens out, the velocity is at 0, that's why it arches back onto the X axis.

The acceleration is because Slope = Velocity.
From the velocity graph, it is going from a maximum positive velocity, to 0, to a negative (but still positive, because it is above the x axis, yeah it's kinda touchy) velocity. So on the acceleration graph, it starts from a maximum positive, goes to 0 (the X axis), and then decends below the X axis.

Hope this helps...