Question

Write the equation of the line which passes through (3, –4) and is perpendicular to the line with equation 4y – x = 1.

Answer 1

Equation is in the form y=mx+b. You know you want it to be perpendicular, which means its slope m should be the negative inverse of the equation given...

4y-x = 1
4y = x+1
y = x/4 + 1/4

So the slope of the equation given is 1/4. This means the slope of the equation we want should be -4: the negative inverse.

Substituting in the point (3, -4) we have yields:
y = mx+b
(-4) = (-4)(3)+b
-4 = -12 + b
b = 8

Therefore the final equation we get is:
y = -4x + 8

Hope this helps! 8D

Answer 2

It does, thanks