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How do you solve this: Limit as x--> ∞ of 12 + 2^x / 6-2^x ? How do you treat the infinity when x is an exponent?
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devide every term by 2^x and then run the limit
so ((12/2^x)+(2^x)/(2^x))/((6/2^x)-(2^x/2^x))
Ohhhh okay so it should give me 12/2^x and such. to then give me 1/1?
1/-1
thank you!
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np
you see why - right?
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