Question

y varies jointly with p and q. When p = 5 and q = 2, y = 80. Find y when p = 4 and q = 5.

y = 20

y = 120

y = 160

y = 240

Answer 1

\[y=pq(k)\]

Answer 2

80 = 5(2)(k)

Answer 3

yup

Answer 4

now find y

Answer 5

80 = 10k

Answer 6

find y when p=4 q=5 and the k you got k=8

Answer 7

nope.

Answer 8

I'm stuck :/

Answer 9

80=10(k) ---- you will find k here

Answer 10

which is 8 right?

Answer 11

right...

Answer 12

now apply the equation again y=pq(k)

Answer 13

but now using p = 4, q = 5 and k =8

Answer 14

you should get the Ynew = (4)(5)(8)

Answer 15

y / (pq) = k
80 / (5•2) = k
8 = k

y / (4•5) = 8
y / 20 = 8
y = 8 • 20
y = 160?

Answer 16

nice. you got nit right

Answer 17

Thanks!

Answer 18

no problem, goodluck solving math problems.