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What is the equation in point-slope form of the line passing through (–2, 0) and (2, 8)?
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First Find Slope
\[\tfrac{y2-y1}{x2-x1}\]
what's that^
barely see that^
then... use....\[y-y1 = m(x-x1)\]
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hold on lemme plug the numbers in.......
find slope m = \[\frac{ y1-y2 }{ x1-x2 }\]
-2 - 2^1 = m(0-8^1)
use any of the point now and find b in the below equation y=mx+b
for (-2,0) and (2,8) m = (8-0)/(2-(-2)) = 8/4 = 2 now consider point(-2,0) we have y=mx+b hence we get -2 =2*0+b therefore b=-2 then equation in point form is y=2x-2
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thank u
welcome
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