Question

Write a slope intercept eqation for the line that passes through (-3,-15) and is perpendicular to -6x + 8y = 3. Show all work.

Answer 1

First change -6x + 8y = 3 to slope-intercept form.
-6x + 8y = 3
8y = 6x + 3
y = 6/8x + 3

y = 3/4x + 3

The slope of a perpendicular line is the opposite recipricol: so 3/4 changes to -4/3.

Now to make the new equation we use the point-slope form: y - y1 = m(x - x1
slope(m) = -4/3
x = -3
y = -15
So:
y -(-15) = -4/3(x -(-15)
y + 15 = -4/3(x + 15)
y + 15 = -4/3x - 20


y = -4/3x - 35

Answer 2

Does that help?

Answer 3

yes it did ty so much