What is the equation of the line passing through (–6, 1) and perpendicular to the line y = –3x + 1 in slope-intercept form?

Question

campbell_st · Answer

the slope of your given line is m = -3 

the perpendicular is the negative reciprocal and must obey the rule

$$-3 \times m_{p} = -1$$

you can solve for $$m_{p}$$

then the equation of your line is in point slope form.  

$$y = m_{p}x + b$$

substitute the x and y values from the point to find b... then you'll have the line