Question

What is the equation of the line passing through (–6, 1) and perpendicular to the line y = –3x + 1 in slope-intercept form?

Answer 1

the slope of your given line is m = -3

the perpendicular is the negative reciprocal and must obey the rule

\[-3 \times m_{p} = -1\]

you can solve for \[m_{p}\]

then the equation of your line is in point slope form.

\[y = m_{p}x + b\]

substitute the x and y values from the point to find b... then you'll have the line