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OpenStudy (anonymous):
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OpenStudy (anonymous):
So based by the Law of Logs log(kx) = logk + logx when k>1 but I'm confused with this one... Is it: y = log(kx) k<1 For ex. k=1/3 y = log(1/3x) y = log1/3 + logx y = log1 - log3 + logx y = logx - log2?
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