Mathematics
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OpenStudy (anonymous):
3x-4/5-2-5x/4=1/2(x+1)
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OpenStudy (anonymous):
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OpenStudy (anonymous):
this is problem you have listed?
OpenStudy (anonymous):
no
OpenStudy (anonymous):
it is like this (3x-4/5)-(2-5x/4)=1/2(x+1)
OpenStudy (anonymous):
good lord i cant use the stupid equation editor
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OpenStudy (anonymous):
haha is there any way you could walk me through it?
OpenStudy (anonymous):
like would i have to multiply each side by 20?
OpenStudy (anonymous):
ya you could just get a common denominator on the left side by multiplying by 3x-4/5 by 4/4, and 2-5x/4 by 5/5
OpenStudy (anonymous):
then what do i do for the right side?
OpenStudy (anonymous):
im assuming the x+1 is in the numerator right
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OpenStudy (anonymous):
no its 1/2(x+1)
OpenStudy (anonymous):
like 0.5(x+1)
OpenStudy (anonymous):
ok so anyways for the lhs we now have 12x-16-10+25x/20 right
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
except its 10-25x not 10+25x
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OpenStudy (anonymous):
you didnt distribute the negative
OpenStudy (anonymous):
oh alright thanks, man i really suck at math
OpenStudy (anonymous):
simplified we now have 37x-26/20=1/2(x+1) right
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
so now what?
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OpenStudy (anonymous):
multiply rhs by 10/10 so we can get a common denominator
OpenStudy (anonymous):
alright i did
OpenStudy (anonymous):
now i have 10/20(x+1)
OpenStudy (anonymous):
37x-26/20=10/20(x+1)
OpenStudy (anonymous):
should have 10x+10/20 on the right hand side
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OpenStudy (anonymous):
oh...
OpenStudy (anonymous):
.5(x+1) is equal to (x+1)/2
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
ok so now i have 37x-26/20=10x+10/20
OpenStudy (anonymous):
so were gonna subtract the right side and put it on the left so your equation should be (37x-26)/20 - ((10x+10)/20)=0
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OpenStudy (anonymous):
alright
OpenStudy (anonymous):
we have a common denominator and you can distribute the negative again so your equation should be (37x-26-10x-10)/20 = 0
OpenStudy (anonymous):
so 27x-16/20=0
OpenStudy (anonymous):
you didnt distribute the negative again
OpenStudy (anonymous):
27x+16/20=0?
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OpenStudy (anonymous):
it should be (27x-36)/20=0
OpenStudy (anonymous):
oh ok
OpenStudy (anonymous):
so now its a simple equation multiply both sides by 20 to cancel out the fraction then add the 36
OpenStudy (anonymous):
so 20 times 27x-36/20?
OpenStudy (anonymous):
ya but that will just cancel out the 20's so youll just be left with 27x-36=0
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OpenStudy (anonymous):
ah i see ty
OpenStudy (anonymous):
so then add the 36 so youll have 27x=36, then divide both sides by 27 so we can get the x by itself
OpenStudy (anonymous):
x=4/3?
OpenStudy (anonymous):
ya
OpenStudy (anonymous):
nice
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OpenStudy (anonymous):
ty