Question

factorise by splitting into two's:
df+6g-6f-dy

i got this:
= (6y-6f) + (df-dg)
= 6(g-f) +d(f-g)

this is wrong, why?

Answer 1

you have a dy in the question and dg in your answer
- have you got question right?

Answer 2

if the question contains dg
df+6g-6f-dg
= 6g - 6f + df - dg

you need to have g-f in both parentheses

= 6(g-f) - d(g-f)
= (6-d)(g-f)

Answer 3

ok ? - i think it must be dg in original question

Answer 4

yeah it was a dg
the answer you gave us wrong though.
the answer in book is (f-g) (d-6)

Answer 5

ok lets expand
(f-g) (d-6) = df - 6f - dg + 6g
- which is the same as the question except terms are moved around a bit
- so the book is correct

now try my answer
(6-d)(g-f)
= 6g - 6f -dg + df
which is also same as the question

both answers are correct - its just that the order of terms in each bracket has changed

Answer 6

do you follow me?

Answer 7

oh i get it now thx.

Answer 8

yw