Question

Lgbariddle!!

is \[\huge a^{\frac mn} = \sqrt[n]{a^m} = (\sqrt[n] a)^m\]

Answer 1

yup

Answer 2

Can be proved

Answer 3

so tell me...what happens when a is negative?

Answer 4

for example \[\huge (-1)^{2/4}\]

Answer 5

\[\huge \sqrt[4]{-1} \implies \text{imaginary}\]
\[\huge \sqrt[4] {(-1)^2} \implies 1\]

Answer 6

you're right, again

Answer 7

that's where your algebra is now shaken :troll:

Answer 8

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