Question

im unsure of my answer

Answer 1

Is my answer undefined?

Answer 2

its 1/1-x - 3/1-x^3 in case the drawing messes up

Answer 3

nopes,defined.try again

Answer 4

ok thanks

Answer 5

is it 3?

Answer 6

do u know the formula :
1-x^3=(1-x)(1+x+x^2) ??

Answer 7

then your function would become:
\(\frac{1+x+x^2-3}{1-x^3}=\frac{x^2+x-2}{(1-x)(1+x+x^2)}\)
can u factorise x^2+x-2 ??

Answer 8

Ooh, this is one of those tricky 'factor out the -1' things, isn't it?

Answer 9

oh right, thanks. What i tried to do was \[\frac{ 1 }{ 1-x } = \frac{ 3 }{ 1-x ^{3} }\] and multiplied both sides by 1-x^3

Answer 10

my bad haha

Answer 11

yes @CliffSedge
so now can u solve it @brygiger