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3x^3+x^2-55x+75=0
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3 and 75 are two coefficients which give you clues to the zeros of this function 3 is possible root so try x=3 f(3) = 3(3)^3 + 3^2 - 55(3) + 75 = 81 + 9 - 165 + 75 = 0 so x=3 is one root (possible roots are factors of 3*75) others worth trying are 5 and -5 i'll try on my calculator hold on a sec
ok -5 is also a root so our expression = (x + 5)(x - 3) (3x +/- a) where a is the other root as last term is + 75 it must be (3x - a) -5*-3*-a = + 75 so a = 5 so we have (x-)(x+5)(3x-5) = 0 and 3 roots are 3, -5 and 5/3
sometimes if you can't only find one root you can use long division or synthetic division to get the other 2 roots
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