Question

A circle has the equation x^2+y^2-3x-4y+4=0 Find the center in terms of (h,k) and any x or y intercepts.

Answer 1

Hint: Complete the square on each of the variables \(x, y\)

Answer 2

Yeah I can get that done, can't seem to find the correct intercepts for some reason.

Answer 3

For the \(x\)-intercepts, we simply plug in \(y=0\), so:
\[
x^2+y^2-3x-4y+4=0\implies\\
x^2-3x+4=0\implies
x\in\mathbb{C}\setminus\mathbb{R}
\]So, there are no \(x\)-intercepts. Try doing the process above, for \(y\).

Answer 4

Thanks!

Answer 5

Sure thing.