kFind an equation for the line perpendicular to 4x+40y=360and goes through the point (-1,9 ). Write your answer in the form y=mx+b .
divide through the equation by 40. we want to isolate or solve for y because we need to put it in slope intercept form (y=mx+b)
i did and i got y=4/40x+9 and i reduce it and got y=1/10x+9
i think you may have overlooked a negative sign. can you see that?
yes. so it will be y=-1/10x-9
close. the 9 stays pos.
so you get y=-1/10 x+9.
then i use that slope to find the equation for this points (-1,9)
yes. so what is the slope and what is the slope of the perpendicular line?
so it would be y=-1/10x+8
the first line has the equation y=-1/10x+9
now what do you think the slope of that line is?
positive 1/10
because from that slope, we us the rule that two lines that are perpendicular have slopes that are negative reciprocals of eachother.
you are close.
the slope is actually -1/10
y=-1/10x+8
whatever the number is in front of the x, that is the slope in slope intercept form
we know that the slope of the original line is-1/10, so what is the slope of the perpendicular line?
10/1
nice. absolutely correct.
so now, you can substitute the coordinates (-1,9) into the equation y=mx+b.
you should e getting something like 9=10(-1)+b.
solving for b gives b=20. so your equation is y=10x+20
so it would be y=10x+1
in order to solve 9=10(-1)+b, you get 9=-10+b; then add 10 to both sides of the equation to get b=20. so your equation is y=10x+20
feel free to ask a question if something is unclear.
i get it. thanks
no problem. take care
you to
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