Question

3(x+4)^2=21.. multiply to (3x+12)^2=21 then do i subract 12 from both sides?

Answer 1

no you should do the (x+4)^2 first, then multiply the result by 3

Answer 2

3(x^2+8x+16)

Answer 3

?

Answer 4

where did you get the 8x from? i got x^2+12 = 21 then 3x^2+36=21

Answer 5

(x+4)^2=(x+4)(x+4)= x^2+8x+16

Answer 6

ooohh
got it now....ack...hate math....it doens't like me....tx for the help

Answer 7

np