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dy/y^2=2x+3x^2 dx
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having trouble integrating?
Hello?
yes
integral of y^-2 ? or the other part?
for y^-2 you can just use \[\int\limits_{ }^{ } y ^{n} = 1/(n+1) * (y ^{n+1})\]
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both
1/y^2\[\int\limits1/y^2\]
so what do you get, using that formula I gave? let me know when you want me to check your result...
-1(y^0)
n=-2
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plug it in to the formula
yes
1/y^2 dy
it's -1/y
ok?
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is right side x^2+x^3+c
hello
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