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Mathematics 19 Online
OpenStudy (anonymous):

dy/y^2=2x+3x^2 dx

OpenStudy (anonymous):

integrate both sides...

OpenStudy (anonymous):

yes but not sure of the outcome

OpenStudy (anonymous):

after integrating LHS= -1/y

OpenStudy (anonymous):

it's ok?

OpenStudy (anonymous):

and RHS= x^2+ x^3

OpenStudy (anonymous):

-1/y=x^2+x^3+c so y=-1/9x^2+x^3)

OpenStudy (anonymous):

and there will be a constant term also...constant of integration

OpenStudy (anonymous):

y=-1/(x^2+x^3)+c

OpenStudy (anonymous):

yes...it's right

OpenStudy (anonymous):

thank you

OpenStudy (anonymous):

:)

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