Question

integral of x^4sinx/1+x^0dx in the interval of (-pi/2, pi/2)

Answer 1

\[\int\limits\limits \frac{x^4 \sin (x)}{1+x^0} \, dx\]
\[\int\limits\limits \frac{x^4 \sin (x)}{1+1} \, dx\]
\[\int\limits\limits \frac{x^4 \sin (x)}{2} \, dx\]

Answer 2

Factor
\[\frac{1}{2}\int\limits x^4 \sin (x) \, dx\]
Then use integration by parts 4 times

Answer 3

how would you do u sub?

Answer 4

u=x^4 dv=sin(x)dx
du=4x^3dx v=-cos(x)

\[-x^4cos(x)+\int\limits\limits_{}^{}4x^3\cos(x)~dx\]