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Mathematics 11 Online
hartnn (hartnn):

How to find inverse of functions like sinc x or signum x or any other functions like this. sinc x= sin x/x signum x = 1 for x>0 =-1 for x<0

OpenStudy (anonymous):

for signum just replace x and y

hartnn (hartnn):

so what would be its inverse ?

hartnn (hartnn):

and for that i should be 1st able to get x in terms of y

OpenStudy (anonymous):

inverse of signum is not a function (think of its graph)

OpenStudy (anonymous):

That y=sin(x)/x one is kinda tricky, so far I have let w=y^-1, the inverse. w=sin^-1(x*w)

OpenStudy (turingtest):

when I define sincx as (sinx)/x wolf is stuck http://www.wolframalpha.com/input/?i=inverse+y%3D%28sin+x%29%2Fx but it seems content to say that the answer is the inverse sinc function http://www.wolframalpha.com/input/?i=inverse+y%3Dsinc+x weird...

hartnn (hartnn):

so i would just assume inverse functions cannot be written as simple equations and close this.

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