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How do i find the perimeter of an equilateral triangle with an area of 9√3???
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find the length of the side first
I tried dividing 9√3 by √3/4. But that didn't work.
P=4x
Yes i know, but i have no sides.
that gives u square of the side u got to root it
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ya, that s^2 now find s
How do I find s, if i only have the area?
I try to divide the area by √3/4
The formula to find the area of an equilateral is: √3/4*s^2
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Area = √3/4 s^2
Yes, and i try to go backwards but i get a bizarre answer?
ya, u DID NOT NOT FIND s u FOUND s^2
9√3 ÷ √3/4= 9 √9= 3
yes
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Ah, i see what i did before, last time i got 3.234. But i used the wrong number in the equation.
okk, cool
Thanks sir!
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