write an equation of the line containing the given point and parallel to the given line. (9, -9);8x-3y=5
I would first rewrite the equation given in slope-intercept form (y=mx+b), and the slope of your answer will be the same as the slope in the given equation. Then, you can plug in the x and y values into your new equation and then solve for b. This will give you the b value.
my slope came out to be 8/3 which makes the equation y=8/3x + 5. the problem only asks for the equation so would this be right or did i mess up somewhere along the way
I don't know if the figures are right, you might want to double check your work if you're unsure. But, that would be a perfectly acceptable format. if it only wants the equation.
Kizzfan911 made a mistake. you get the equation y = (8/3)x - (5/3). Now we know the slope so plug in the point given into y = (8/3)x + b and solve for b giving you the answer.
i came out with -33 so if smstevns is correct in his steps that would make the answer y = (8/3)x + 33 right?
sorry y = (8/3)x - 33
I just worked out the problem, and that's the answer I got. Looks good.
thank you kuromeru
No problem, happy to help.
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