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f(n)=2n+1 (n∈N) if n is a prime number or f(n)=n/p,p is the most prime factor of n,then f(f(...f(n)...))=3 or 5,is this correct?
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is'nt 2n+1 odd numbers,3,5,7...
i dont understand it
f(f(...f(n)...))=3 or 5 ----------- how many f's? n times?
if its n times f...then its not a true statement because : \[f^{15}(15)=15\]
No,not n times,any times,it always equal 3 or 5.
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are we to stop when 3 or 5 results...
yes ,stop at 3 or 5 result.
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