A bullet is fired from with a velocity V (m/s) at an angle q with the horizontal direction. At the highest point of its motion, it explodes into two unequal masses: 2m/3 and m/3. Is the time taken by the smaller piece(m/3) to drop to the floor is shorter than the time taken by the 2m/3 piece?

Question

dumbcow · Answer

no the time it takes to fall is independent of mass

$$h(t) = -4.9t^{2} + V \sin(q)t$$
and when they reach the highest point, there upward velocity will reach zero

dumbcow · Answer

of course , depending on the force of the explosion, one piece may be propelled farther up than the other, hence hit the floor at a later time

anonymous · Answer

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