How many solutions does the system have?

x = -4y + 4
2x + 8y = 8
A. one solution
B. two solutions
C. infinitely many solutions
D. no solution

Question

How many solutions does the system have?

x = -4y + 4
2x + 8y = 8
	A. one solution 	
	B. two solutions 	
	C. infinitely many solutions 	
	D. no solution

parthkohli · Answer

Multiplying the first equation by 2:$$2x = -8y + 8 $$

parthkohli · Answer

Also, subtracting 8y from both sides in the second equation:$$2x = -8y + 8$$

anonymous · Answer

There is a lot of solutions

parthkohli · Answer

We now have the following equations:$$2x = -8y + 8\2x = -8y + 8$$

parthkohli · Answer

A lot? Uncountable! Infinity!

parthkohli · Answer

lol

anonymous · Answer

yes a very lot

parthkohli · Answer

A lot lot lot lot!

anonymous · Answer

You can see that without solving the system.

anonymous · Answer

You can mentally arrange the unknows at the left hand side. 
and see that the second equation is the first one multiplied by 2

anonymous · Answer

so you have only one equation with two unknows. that means a lot of solutions.