Three coins are tossed up in the air. What is the probably that two of them will land heads and one will land tails? please show strategy to solve.thanks

Question

anonymous · Answer

Each has prob=50% heads -> p=0.5

parthkohli · Answer

It's pretty simple, actually. Multiply probabilities of independent events here:

P(Heads) * P(Heads) * P(Tails)

anonymous · Answer

And P(H)=P(T).
Voila!

anonymous · Answer

The answer key is giving the answer as 3/8. Wondering how they solved. thanks

parthkohli · Answer

It should be 1/8 :|

anonymous · Answer

Maybe because it could be any of the three possible pairs of coins?

anonymous · Answer

It didn't specify which coins.

anonymous · Answer

It would be 1/8 if it specified the first two heads and the last one tails, but it asked for any two of them heads and the other tails. There are 3 possible pairs you can draw from three things.