f(x) ={x^2+ x - 12 }/{3x^2+ 9x - 12 }

what are the asymptotes for x and y?

Question

f(x) ={x^2+ x - 12 }/{3x^2+ 9x - 12 }

what are the asymptotes for x and y?

anonymous · Answer

Let the denominator = 0 => x = ....

anonymous · Answer

huh?

anonymous · Answer

Do you know where the denominator in your f(x) Is?

anonymous · Answer

no... and the question says: Find the equations of the horizontal asymptotes and the vertical asymptotes of f(x).

anonymous · Answer

Find x = ...
means find vertical asymptotes of f(x)

anonymous · Answer

denom.. =-12?

anonymous · Answer

So you have no idea what is denominator in a fraction !?!

anonymous · Answer

The denominator is the bottom half of a fraction lol.

anonymous · Answer

Then what is this denom.. =-12?

anonymous · Answer

I substituted? f(x)=0

anonymous · Answer

Anyway, let "the bottom half of a fraction" = 0 , 
NOT f(x) = 0

anonymous · Answer

x= -4 and 1

anonymous · Answer

Here you go, there are 2 vertical asymptotes x = 1, x = -4

anonymous · Answer

that's not right.

anonymous · Answer

It's just 1. you have to figure out which one is the REAL vertical asymptote.

anonymous · Answer

So you know how to simplify the fraction, right?

anonymous · Answer

factor..?

anonymous · Answer

what about the horizontal asymptote?

anonymous · Answer

After you simplify:
f(x) = ...?

anonymous · Answer

x-3/3x-3

anonymous · Answer

Yep, since horizontal asymptote y = lim f(x) when x approach to inf 
=> y = 1/3

anonymous · Answer

thank you.