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Ok, the next problem is 1+5+9+...+401 So, first thing I did was use the arithmetic sequence formula a to the nth term=a1+(n-1)d So i plugged in 401=1+(4n-4) Ended up getting 101 for n Then I used the sum of an aritmetic series formula s(101)=101(1+401)/2 Ended up with 40602/2 And got 20301 as the sum of all 101 terms. Is that correct Igbasallote?
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yup
Thanks man
welcome
next time you can just tag i.e. @lgbasallote
Just needed to teach myself (With some help) the method). And i will do that next time, sorry
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