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Find all values of x for which the function is differentiable for y = sin x - x cos x.
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y'=Cosx-(x*(-Sinx)+Cosx)
y' = Cosx + x*Sinx - Cosx = x*Sinx
that's a continuous function, so y is differentiable for all x
Okay, thank you so much!
How did you find y' though?
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y' = derivative of y
y = sin x - x cos x. Derivative of Sin x is Cos x To find the derivative of x*Cosx, use the product rule
Oh okay. Thanks!
(f*g)'=f*g'+g*f'
and that's the product rule if ur wondering
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Thanks :).
How would you do it for y = \[\sqrt{(x-1)/(1+x ^{2})}\]
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