Mathematics
10 Online
OpenStudy (anonymous):
How to solve:
log(x+2) + log(x-1) = 1
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OpenStudy (anonymous):
Hint: loga + logb = log(a/b)
OpenStudy (anonymous):
Does it help?
OpenStudy (anonymous):
Hmm give me a sec
OpenStudy (anonymous):
Not really :$ the answer is 3 and that just gives me a quadratic formula
OpenStudy (anonymous):
Are they base 10?
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
I assume
OpenStudy (anonymous):
1=log10
OpenStudy (anonymous):
So, log(x+2) + log(x-1) = 1
log{(x+2)(x-1)} = log10
OpenStudy (anonymous):
That may help
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OpenStudy (anonymous):
Do you know what to do when both 2 sides have the same base?
OpenStudy (anonymous):
I don't think so (chlorophyll)
OpenStudy (anonymous):
So learn the rule, both logs will be CANCELLED out :)
OpenStudy (anonymous):
really? okay, but then I'm still confused :$
OpenStudy (anonymous):
okay, so it would still be (x+2)(x-1) = 10
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OpenStudy (anonymous):
x^2 +x -2 = 10
OpenStudy (anonymous):
or x^2+x-12 actually
OpenStudy (anonymous):
=0
OpenStudy (anonymous):
... solve the quadratic equation?
OpenStudy (anonymous):
and then is the positive root just my answer?
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OpenStudy (anonymous):
Perfect! I'm waiting for your x = ...?
OpenStudy (anonymous):
3
OpenStudy (anonymous):
Wow, why's so fast!
Hmm...
OpenStudy (anonymous):
Anyway, correct!
OpenStudy (anonymous):
Questions?
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OpenStudy (anonymous):
um no thanks :) will try that with the next question now!