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Mathematics 17 Online
OpenStudy (anonymous):

PLEASEEE HELPPP :) I NEED THE AWNSER Nancy drew parallelogram ABCD as shown On the same grid she will draw parallelogram PQRS similar to parallelogram ABCD with the ratio of corresponding side lengths PQ and AB equal to 4 : 1. If the coordinates of vertex P are (-8, -5), what could be the coordinates of vertex Q 4, 6) (-4, -1) (0, -5) (8, -5)

OpenStudy (anonymous):

OpenStudy (anonymous):

Simply look at line segment AB first. Since the y-values are the same, the points are simply separated by an x-distance, which by subtraction, is 4. So since AB is 4 units in length, if PQ is 4:1 with AB, then PQ is 4 x 4, or 16 units in length. So now consider the point P (-8, -5). If the y-coordinate is the same for both P and Q, then simply add 16 to the x of P to obtain the x of Q. -8 + 16 = 8 So point Q is at (8, -5) , or the last choice :D

OpenStudy (anonymous):

THANKS ALOT that was my original awnser :)

OpenStudy (anonymous):

Fantastic! So you're doing it right :D

OpenStudy (anonymous):

woohoo wanna try to help me with another plz?

OpenStudy (anonymous):

It'd be my pleasure :)

OpenStudy (anonymous):

a trapezoid is drawn on a grid with vertices at P (-5, 7), Q (-2, 7), R (2, 3), and S (-8, 3). Trapezoid UVWX will be drawn similar to Trapezoid PQRS with side UV corresponding to side PQ. The point (2, -2) will be the location of vertex U and point (8, -2) will be the location of point V. What will be the coordinates of vertex X? Show all your work or explain your reasoning

OpenStudy (anonymous):

its the only one i truley dont get!!

OpenStudy (anonymous):

Alright let me think about it :)

OpenStudy (anonymous):

k thx so much bro

OpenStudy (anonymous):

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OpenStudy (anonymous):

ok so now how ud come up with that so i can type my steps???:)

OpenStudy (anonymous):

Nevermind I overcomplicated it, i'm sorry. the y-coordinates of PQ are the same, so the x-distance is 3. Notice for U and V the x-distance is 6. So essentially all the sides are doubled in length.

OpenStudy (anonymous):

ok ok i get it so for my awnser how would i word it, just like what you said or something else???

OpenStudy (anonymous):

well you need the point of X, so we need to find that :P

OpenStudy (anonymous):

oh yea i kinda lost track for a second lol. so we needa graph huh

OpenStudy (anonymous):

Okay, so if we look at the relation of point P (-5, 7) and S (-8, 3) we see they differ by x=3 and y=4, so if we simply double that relationship with U and X, we should get our point. So if U is at (2, -2), the we should move left 3x2 x units and move down 4x2 y units. So if we move left 6 and down 8, we get point (-4, -10) for X :D

OpenStudy (anonymous):

ohh em gee ur a genius thxs i deff get what ur tlking about :D

OpenStudy (anonymous):

hahaha :P glad i could help.

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