Question

Help Please! (Attachment to come.)

Answer 1

I don't understand why C doesn't equal 11. And i have no idea what the second part of the question means! Can anyone help me?

Answer 2

shld be -11

Answer 3

because you have 12, but you originally had 1, so that 11 had to go somewhere.. i think

Answer 4

Oh! Whoops! Thanks! do you have any idea what the second part of the question means?

Answer 5

1

Answer 6

that should go into that box, check if it's right and then I'll tell u how i got it.

Answer 7

no, it's not 1...

Answer 8

uhmm let's see..

Answer 9

ok try -11

Answer 10

Yes! That worked! How'd you do that?

Answer 11

cool, I see..

Answer 12

now to explain that.. uhmm wait let me think of how to explain it..

Answer 13

Basically what they meant is, f(x) cannot be a certain range of numbers, and that is correct, since:
3(x+2)^2 can never be negative.. so I thought what is the smallest value that it can take on, and that is where I made my first mistake.

Answer 14

I assumed that it's smallest value would be when x=0, and the value would be 3*2^2=12
and 12-11=1, so y had to be greater or equal to 1, but I was wrong. My logic was right though, I just picked the wrong x value..

Answer 15

I should have picked x=-2, that's when you'll get: 3(-2+2)^2=3*0^2=0, and 0-11=-11.
Since 0 is the smallest value that 3(x-2)^2 can take on, the function has to be >=-11, since 0-11=-11

Answer 16

So basically you can't get anything smaller than -11, you can't have -1-11=-12..

Answer 17

idk if that explains it, but i tried. Any questions?

Answer 18

No questions, you explained it very well! Thank you very much! :D

Answer 19

great