Question

please help solve this question (show your work)!!!!

use limit of x->a f'(a)=(f[x]-f[a])/(x-a) to find the derivative of f[x]=x^2 +4, a=1

Answer 1

help!!!! please!!!!!

Answer 2

Solve this:
\[ \lim_{x \rightarrow a} \frac{f(x) - f(a)}{x - a} = \lim_{x \rightarrow 1} \frac{x^2+4 - (1^2+4)}{x - 1} = \lim_{x \rightarrow 1} \frac{x^2-1}{x-1}\]