how to find csc(x)=sec(x) for x from 0,2pi

Question

anonymous · Answer

$$\frac{1}{sinx} = \frac{1}{cosx}$$

multiply by sinx

remember:
sin/cos = tan

tanx = 1

solve this in the given region and you have your values of x

anonymous · Answer

im happy to check your answers so feel free to post them if you want

anonymous · Answer

yeah why cant i do sinx=cosx   sinx=sin(pi/2-x) .:x=pi/2-x   2x=pi/2 x=pi/4    missing soln?

anonymous · Answer

yeah missing solutions, i wouldn't reccomend that method, although it is valid. this is the correction:

you're using cos(x) = sin( (pi/2) -x)

but we could just as well use cos(x) = sin( (5pi/2) -x)

and get the other solution

anonymous · Answer

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