Question

Sandwich theorum to confirm
lim (x^2)sin(1/(x^2)) = 0
x->0

Answer 1

I know I have to break it off into parts but I dont know what.
Would it be
Lim x^2 and Lim -x^2
x->0 x->0

Answer 2

Lim x^2 > lim (x^2)sin(1/(x^2)) > Lim -x^2
x->0 x->0 x->0

???

Answer 3

yes that is correct :)

Answer 4

Yaaaaaa!

Answer 5

it also made me notice you can do sinx/x with the squeeze theorem too :)
check you other post